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Electron density

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Top 10 Contributor
Posts 21
Jana Posted: 11-25-2008 2:45 PM

What is the difference between electron density \rho(r) and probability density |\Psi(r1,..rN)|^2? Can someone explain?

How comes \rho(r) integrates to N and |\Psi|^2 integrates to 1? What does it mean?

Top 10 Contributor
Posts 10

Do you mean \rho(r) integrates to N?

Because electron density is the sum over N electrons of the probability density of finding an electron at r. The probability integrates to 1, that would make the integration of \rho(r) = N

Top 10 Contributor
Posts 21

Yes, I meant \rho(r) integrates to N. I corrected the typo. Your explanation sounds plausible, let me improve it a little:

Because the electron density is defined as the probability density of finding an (any) electron at r, and since we have N electrons, the probability is N over all space.

How can we prove it? Hint: write down the definition of \rho(r) in terms of wave function \Psi(r1,r2...rN).

Top 10 Contributor
Posts 14

I guess the process to prove it is similar to that on page138 of Modern Quantum Chemistry by A Szabo and N Ostlund, I have wrote the proof down. Please find it in the attachment.

8168.answer.pdf

Top 10 Contributor
Posts 4

I think this is the exercise 3.11(P139) in Ostlund's Quantum Chemistry book. because the density operator \rho(r) is an one-electron operator,  its integeral is similar to that of the first item of Hamiltonian O1. Therefore we can use the equation of case 1 in Table 2.5(P72) and replace h with \delta(r-ri). Then it is easy to derive the equation(3.142)P(138). 

Top 10 Contributor
Posts 21

Great! But what is the relationship between \rho(r) and \psi(r1,r2,...rN)? Can you write down the equation?

Top 10 Contributor
Posts 4

\rho(r) = < \psi(r1,r2...rN) | sum_i{delta(r-ri)} | \psi(r1,r2,...rN) > , is it right?

Top 10 Contributor
Posts 21

Yes, but I want to have the formula without the density operator. Hint:  \rho(r) is the integral of \psi(r1,r2,...rN) ...

Top 10 Contributor
Posts 26

rho(r) = N *integral( dr2 dr3 dr4 ... drN | psi(r1,r2,r3,r4,...rN)|**2)         leaving out any one r ( dr1 here ), and multiply by N so that when we integrate over the remaining r we get N

->   intergral (rho(r) dr) = N*integral( |psi(r)|**2 dr) = N     ? 

Top 10 Contributor
Posts 21

Yes.

Top 10 Contributor
Posts 14

Yes, the answer seems right. But I still feel a little puzzled about this expression. Please refer to my attachment. I really want to know what the meaning of the part2 and part3 of the equation in my attachment is, or, In other words, why we need part2 and part3?

 

7585.confusion.pdf

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